Monday, February 25, 2013

Vocab

Chris Dayal
Honors Physics
Period 6/7
Mr. Kirch

1. Lab: The Mathematical Models for a constant Linear Acceleration

2. Purpose: To use the mathematical models for a identical additive acceleration to predict and test how high an inclination tossed vertically will rise. Also, we need to explain how selective information for exertion along an incline supports the model of a provide one-dimensional acceleration both mathematically & graphically.

3. Apparatus: Video, Incline, surface Ball, Ruler, Books, Stopwatch, Meter Stick, Microsoft Excel

4. Sample Calculations:

5. Data:
d (cm)| tavg (sec)| tavg2|
0| 0| 0|
50| 1.31| 1.72|
60| 1.62| 2.63|
70| 1.76| 3.10|
80| 1.81| 3.28|

6. analysis:

Included in Summary

7. Summary:

The main purpose for the laboratory was to use the given mathematical models for a uniform linear acceleration to test and predict exactly how high an purpose tossed vertically will rise. In addition, we must explain how data for motion along an incline supports the model of a uniform linear acceleration in terms of both mathematically & graphically standpoints. This was achieved by first watching a video of a ball being tossed up in the air.

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Since the whole video was about 30 frames long and we mandatory to predict vi, we first counted exactly how many frames it took for the ball to take a shit to its pinnacle point from when it left the persons go past. After, we heedful the distance from when the ball left the persons hand to the highest point. Since vf would be at the highest point (climax) (which would be 0m/s), we wherefore blocked in all of the values into the d / t = (vi + vf) / 2 comparison to find out and solve for vi, the unknown variable. We then tested this by using the d/t equation by using the first frame, using 1/30 m/s for the time and saw how long it took to withdraw from the persons hand to the first frame. We then careful this for the distance. Our prediction was roughly 5.75m/s and tested value proved to be 6.4m/s. Some differences in our...If you want to get a full essay, order it on our website: Orderessay



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